![]() ![]() So angle of incidence is equal to angle of reflection this is true under special conditions. #ANGLE OF INCIDENCE EQUALS ANGLE OF REFLECTION FREE#Combine this with the fact that without free electrons it is VERY difficult to smooth a surface, it will give you no chance for a decent (specular) reflection.As we know according to the law of reflection angle of incidence is equal to angle of reflection this is true if and only if, if the surface on which light strikes is smooth. angle of reflection n (General Physics) the angle that a beam of reflected radiation makes with the normal to a surface at the point of reflection Collins English Dictionary Complete and Unabridged, 12th Edition 2014 © HarperCollins Publishers 1991, 1994, 1998, 2000, 2003, 2006, 2007, 2009, 2011, 2014 angle of reflection n. When a new photon is emitted, it will run into other atoms (it's not at the surface anymore!) and keep the reaction going until at the surface, photons are reflected in random directions. ![]() ![]() So why does this not happen at any surface? Well, the above only applies to surfaces with lots of electrons, found in materials where electrons are free - for example metals! Surfaces where all electrons are bound will not absorb the photons immediately - they'll penetrate the first few layers of atoms unhindered until by chance they are absorbed. No longer the photons that are emitted upwards are in phase with eachother, but only the photons that are emitted at the exact same angle as the incident photons are in phase. When an electron emits a photon, and there are many photons around it who all have the same phase and direction, the emitted photon will copy the phase and direction of the photons around it! So very quickly, all photons that are emitted in random directions die out and only photons that are emitted perfectly in phase with eachother remain. Since the angle of reflection equals the angle of incidence, the. Now something interesting happens - something that also explains why lasers work. The angle of incidence, the angle between the incident ray and the normal N is given as 45o. Photons that are in phase (all the photons that are emitted upwards) will constructively interfere with eachother. Photons that are out of phase will tend to cancel eachother out. The photons that are emitted at an angle however, will be out of phase with eachother (since there is a distance between the electrons, if two photons are emitted at any angle at the same time, there will be a slight delay between them). Now you have many electrons that are being bombarded by even more photons, all emitting photons in many directions. Let's assume that the beam of light hits the reflecting surface directly from above, so the angle of incidence is 0 degrees. As we know according to the law of reflection angle of incidence is equal to angle of reflection this is true if and only if, if the surface on which light. Hint: this is where the wave nature of light comes into play. If this is the only electron in the neighbourhood that releases a photon, it will go in any random direction. When it does, it needs to get rid of its extra energy. This chance increases over time, so it's pretty certain that it will jump back quite quickly. Thus, there is a chance that it spontaneously jumps back to a lower energy state. This does not last long the electron left an "empty" energy state below it, which is an energetically more favorable position for it. When a photon hits an electron, its energy gets absorbed and the electron goes into a higher energy state. It runs into a wall of atoms - lots of nuclei surrounded by electrons (also energy packets - there's more to it but let's not write out all of quantum mechanics here). Now let's zoom in and look at what happens when the photon hits any material. Not because we must, but because we can! There's a TL DR below.Ī beam of light can be thought of as a stream of energy packets (photons, which are the quanta of light - lots of interesting words to look up in the dictionary already). However, to quote Leonardo DiCaprio: we need to go deeper. The answer by harshit54 is very concise and clear and gives you answers in multiple layers of understanding. ![]()
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